Re: Using isMemberOfClass with a tree of subclass of NSManagedObject

FROM : Yoann GINI
DATE : Sat Jun 28 20:41:39 2008

Nota : userInfo pointer of kind NSNotification is a mistake, it's a 
NSDictionary of course.

Le 28 juin 08 à 19:58, Yoann GINI a écrit :

> A part of code (this is a simply try code for a R&D):
>
> @interface root :  NSManagedObject
> @interface song :  root
> @interface artist :  root
> @interface modification :  NSManagedObject
>
>
>
> -(void)dataBaseHaveChange:(NSNotification*)notification                //I 
> receive here the notification of a CoreData modification
> {
>     NSNotification*            userInfo    = [[notification userInfo] retain];
>     NSSet*                objectsSet    = nil;
>     
>     objectsSet = [userInfo valueForKey:NSInsertedObjectsKey];
>     for (NSManagedObject* modEntry in objectsSet) {
>         if ([modEntry isKindOfClass:[root class]]) {
>             //do something
>         }
>     }
>
>     //The same things for modified and deleted object
> }
>
>
> The aim of that is to record changement in the data base, but the 
> record is in data base too, and I don't want to catch the 
> modification of kind "modification", the solution retained for do 
> that it's do something only if the managed object is a subclass of 
> root. But actually the condition is never verified...
>
>
>
>
> Le 28 juin 08 à 19:30, Mike Abdullah a écrit :
>

>> Post some code.
>>
>> Mike.
>>
>> On 28 Jun 2008, at 18:25, Yoann GINI wrote:
>>

>>> Ho sorry, of cours it's isKindOfClass, I've this problem since 2 
>>> days and I've try all similar method by despair !
>>>
>>> With isKindOfClass I've always a NO in return...
>>>
>>> Le 28 juin 08 à 19:15, Owen Yamauchi a écrit :
>>>

>>>> On Sat, Jun 28, 2008 at 9:58 AM, Yoann GINI
>>>> <yoann.<email_removed>> wrote:

>>>>>    Do you have an idea ?
>>>>>

>>>>
>>>> Use -isKindOfClass: instead. -isMemberOfClass: only tells you if an
>>>> object is an instance of that specific class. -isKindOfClass: 
>>>> includes
>>>> all superclasses as well.
>>>>
>>>> Owen
>>>> [forgot to reply-all]

>>>
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>>

>
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