Re: Why does this leak memory?

FROM : Jamie Curmi
DATE : Sat Jan 18 22:32:36 2003

Hi All,

I should point out, every time this is called, more leaks occur. It
isn't just the first call of [NSImage imageNamed:@"Connected"] that
leaks (I realise that gets cached).  It appears that every call of
copy, followed by the release, ends up with more memory leaked.

MallocDebug shows the leak - and it increases with each call. 
Similarly "top" shows the vsize increasing with each call.

Am I missing something here?

Jamie

On Sunday, January 19, 2003, at 03:50  AM, j o a r wrote:

> *When* does it leak? You create a temporary, autoreleased, object like
> this:
>
> [NSImage imageNamed:@"Connected"]
>
> ...then you make a copy of that object. Now you have two objects, one
> autoreleased and one with a retain count of one. After that you
> release the copied object, but the autoreleased object will remain for
> the duration of the current event loop. If you sample directly after
> releasing the copied object you would notice that you still have one
> object around - and this is as it should.
>
> If you create a lot of autoreleased objects in a loop, you might
> consider using local autorelease pools. There is plenty of
> documentation on that topic, both in the docs from Apple, in the list
> archives, and online - notably on stepwise.com.
>
> j o a r
>
>
> On Saturday, Jan 18, 2003, at 13:59 Europe/Stockholm, Jamie Curmi
> wrote:
>

>> Maybe this is a stupid question.  Could someone tell me why the
>> following code leaks memory (under 10.2.3)?
>>
>>  NSImage * icon = [[NSImage imageNamed:@"Connected"] copy];
>>  [icon release];
>>
>> Of course, that isn't what my program does.  But my program leaks,
>> and I've simplified it down to that.  I thought that the "release"
>> would cleanup the copy of the icon I've made, but that doesn't seem
>> to be the case.

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